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Wednesday, 31 October 2012

how genrate 8 disit rendom number

    public string Get8Digits()
    {
        var bytes = new byte[4];
        var rng = RandomNumberGenerator.Create();
        rng.GetBytes(bytes);
        uint random = BitConverter.ToUInt32(bytes, 0) % 100000000;
        return String.Format("{0:D8}", random);
    }

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